[Free] IIT JAM Physics Test Series 2023 : Electronics – (Feedback and Oscillator)

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Now In this Post of IIT JAM Physics Test Series, you will get a test of the topic Feedback and Oscillator of Chapter Electronics. There are total 7 Questions given below also Answers are attached at the end of the test so that you can verify your answers after completing the test. So, Practice these Questions and Do your Best. Also Solve IIT JAM Physics Previous Year Question Paper. And Don’t Forget to Share with Your Friends.


[Free] IIT JAM Physics Test Series 2023 : Electronics – (Feedback and Oscillator)


Q1. An amplifier has a voltage gain Av = 1000, input impedance 1 kΩ and output impedance 500Ω. A fraction βv = 0.1 of the output voltage is fed back in the serie in opposition to the input voltage. The input and output impedance after the feedback are given respectively by the approximate values.

  • (a) 100 kΩ and 5 kΩ
  • (b) I kΩ and 5 kΩ
  • (c) 10 kΩ and 50 kΩ
  • (d) 100 kΩ and 100 kΩ

Q2. An amplifier of gain 1000 is made into a feedback amplifier by feeding 9.9%% of its output voltage n series with the put opposing. If fL = 20 Hz and fH = 200 kHz for the amplifier without feedback, then due to the feedback.

  • (a) The gain decrease by 10 times
  • (b) The output resistance increases by 10 times
  • (c) The fH increases by 100 times
  • (d) The input resistance decreases by 100 times.

Q3. An amplifier has a 40 dB gain. Its gain may change by 10 % due to change in its parameters. Negative feedback is used to reduce this change only to 1%. Then the value of feedback factor B is

  • (a) β = 0.1
  • (b) β = 10
  • (c) β = 0.09
  • (d) β = 0.001

Q4. An amplifier with negative feedback has a voltage gain of 100. It is found that with feedback an input signal of 0.6 V is required to produce a given output whereas without feedback the input signal must be only 30 m\ for the same output. Then the voltage gain without feedback A and feedback factor β arc A.

  • (a) A=1000, β = 9/1000
  • (b) A=1000, β = 10/1100
  • (c) A=1000, β = 13/1200
  • (d) A=1000, β = 11/1200

Q5. The input impedance of an amplifier increases by the introduction of feedback. It is due to

  • (a) positive feedback
  • (b) current series negative feedback
  • (c) current shunt negative feedback
  • (d) voltage shunt negative feedback

Q6. In a RC coupled amplifier, the reduction in voltage gain in the high frequency range results due to:

  • (a) coupling capacitor
  • (c) series capacitance in the circuit
  • (6) shunt capacitance n the circuit
  • (d) bypass capacitor in the inner circuit

Q7. In a amplifier the negative feedback is a process where a portion of output signal is ted to the input of the normal amplifier with the condition that the input signal is:

  • (a) in phase
  • (b) 90° out of phase
  • (c) 180° out of phase
  • (d) any arbitrary phase

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Answer Key (if you find any answer wrong, feel free to Correct us)

01.(a)06.(a)
02.(c)07.(c)
03.(c)
04.(b)
05.(b)

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